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How do i solve 2k^2-5k-18=0
4 months ago
Q:
how do i solve 2k^2-5k-18=0
Accepted Solution
A:
Answer:factor left the side of the equation (2k_9)(k+2)=0set factors equal to 0 2k_9=0 or k+2=0 the answer is K= 9/2 or K =-2