MATH SOLVE

3 months ago

Q:
# five years ago a man was seven times as old as his son. five years hence the gather would be three times as old as his son. find their present ages

Accepted Solution

A:

father = x

son = y

x-5 = 7(y-5)

x +5 = 3(y+5) solve the system

x-5 = 7y-35

x+5 = 3y +15

x-5 = 7y-35

-x-5 = -3y -15

-10 = 4y -50

+50 +50

40 = 4y

10 = y

Solve for X

x+5 = 3(10) + 15

x+5 = 45

x = 40

The father is 40yrs old and the son is 10yrs old.

son = y

x-5 = 7(y-5)

x +5 = 3(y+5) solve the system

x-5 = 7y-35

x+5 = 3y +15

x-5 = 7y-35

-x-5 = -3y -15

-10 = 4y -50

+50 +50

40 = 4y

10 = y

Solve for X

x+5 = 3(10) + 15

x+5 = 45

x = 40

The father is 40yrs old and the son is 10yrs old.